I can see why but why doesn't the base voltage add on to 6? Because that what I have been stuck on. If Ve = Vc + VB, then if Vc = 6, then voltage would magically be created.... I have no idea why this is not the case.
if you consider the moment when the voltage is switched on at the supply, the potential divider of the 5k and the 10k will put an initial 4V at the base.
The transistor will conduct through its base-emitter (from the 6V rail through the 5k resistor across the b/e and to the negative rail.
