AK47frizzle

As soon as the transistor switches on, the emitter resistor is connected to the potential divider circuit through the B-E. The 6V sees a 5K resistor in series with effectively two 10k resistors in parallel. This will put around 3V at the base, still enough to keep the transistor on. The important thing is that when the transistor is hard on,its resistance between collector and emitter is virtually zero, a short circuit. This effectively connects the 6V rail voltage to the top of the emitter r...

The transistor is a switch. When its off, the emitter voltage is 0V (transistor not conducting is effectively a high resistance = open circuit).

When its switched on by applying a voltage, its emitter output will increase. In this case to 6V. Normally you use a resistor in the collector leg to reduce this.

In an emiiter follower circuit, you take the voltage from the emitter which is what this circuit is.

Eep, I USED to know how to do this. :S