Lozart
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- Jun 24, 2013
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I see what you're getting at but I think you're coming at it the wrong way around.
Motor stall occurs when the mechanical load on the motor exceeds the strength of the flux in the motor windings. If you mechanically stall a motor connected to an unlimited power supply the motor will attempt to draw more and more current until it reaches the maximum stall torque. Usually motors are wound with the correct gauge of wire to reduce the possibility of burnout at this point but with a small or cheap motor it is a possibility.
However you won't achieve maximum stall torque in the condition of a low output battery. The motor WILL stall, but at an earlier point in the torque curve and hence at a lower current draw (the maximum the battery can in fact supply) which is less likely to damage the motor. It is physically impossible for the motor to draw more current than is available from its power source, if that level of current does not exceed the maximum current capacity of the motor windings it will not get damaged.
Motor stall occurs when the mechanical load on the motor exceeds the strength of the flux in the motor windings. If you mechanically stall a motor connected to an unlimited power supply the motor will attempt to draw more and more current until it reaches the maximum stall torque. Usually motors are wound with the correct gauge of wire to reduce the possibility of burnout at this point but with a small or cheap motor it is a possibility.
However you won't achieve maximum stall torque in the condition of a low output battery. The motor WILL stall, but at an earlier point in the torque curve and hence at a lower current draw (the maximum the battery can in fact supply) which is less likely to damage the motor. It is physically impossible for the motor to draw more current than is available from its power source, if that level of current does not exceed the maximum current capacity of the motor windings it will not get damaged.